Example 1
A-1-a gravel: No10=40, No40=20, No200=5, PI=3 (GI = 0 by definition)
Given
- passing no10
- 40
- passing no40
- 20
- passing no200
- 5
- plasticity index
- 3
Assumptions
- Classification per AASHTO M 145 by left-to-right elimination: the FIRST group whose limits all pass is the classification.
- Result: A-1-a (0) — stone fragments, gravel and sand, general subgrade rating excellent to good.
Solution steps
Granular screen
With 35% or less passing the No. 200 sieve the soil is a granular material (A-1, A-3, A-2 families); more would make it a silt-clay material (A-4 to A-7).
F = 5 % ≤ 35 % → granular
Test A-1-a
Stone fragments/gravel: tight limits on all three sieves and PI ≤ 6.
passes: passing No. 10 = 40 % ≤ 50 %; passing No. 40 = 20 % ≤ 30 %; passing No. 200 = 5 % ≤ 15 %; PI = 3 % ≤ 6 %
Group index for A-1-a
By definition the group index of A-1, A-3, A-2-4 and A-2-5 soils is always taken as zero.
GI = 0
= 0
Classification: A-1-a (0)
Group A-1-a — stone fragments, gravel and sand; general subgrade rating excellent to good. Reported with the group index in parentheses.
Results
Group index GI (whole number)
0
Percent passing the No. 200 sieve (F)
5
Where this answer was checked
- source
- AASHTO M 145 classification table (as tabulated in the NCEES FE Reference Handbook) — A-1-a limits: No10 ≤ 50, No40 ≤ 30, No200 ≤ 15, PI ≤ 6; GI ≡ 0
- verified by
- hand-recomputed
- derivation
- 40 ≤ 50 ✓, 20 ≤ 30 ✓, 5 ≤ 15 ✓, PI 3 ≤ 6 ✓ → first group passes → A-1-a. GI of A-1 soils is always 0.